The volume of a right circular cone is 462 cm . If its height is 12 cm, then the area of its base (in cm ) is:

115.5

We know that,

Volume of a cone = \(\frac{1}{3}\) × π × r² × h

Area of base = πr²

We have,

Volume of a right circular cone = 462 cm³.

Height = 12 cm.

According to the question,

= \(\frac{1}{3}\) × π × r² × h = 462

= \(\frac{1}{3}\) × π × r² × 12 = 462

= πr² = \(\frac{462}{4}\) = 115.5