How many unpaired electrons are present in \(Ni^{2+}\)?
Answer & explanation
Correct answer: option 3
The correct answer is option 3. 2.
Nickel has an atomic number of 28.
The electronic configuration of \(Ni\) is \([_{18}Ar]4s^2 3d^8\)
When nickel forms a \(Ni^{2+}\) ion, it loses 2 electrons, leaving it with 26 electrons to form \(Ni^{2+}\) it loses its electrons from the \(4s\)-subshell and the configuration changes to:
It has 2 unpaired electrons.