ΔABC is a right-angle triangle at B. If tan A$=\frac{5}{12}$, then sin A + sin B + sin C will be equal to :

$1\frac{5}{13}$ $2\frac{4}{13}$ $3\frac{1}{13}$ $2\frac{1}{13}$

$2\frac{4}{13}$