Which of the following is an oxidizing agent?

Mn(CO)₅

The correct answer is option 2. \(Mn(CO)_5\)

We must first understand oxidizing agents since they aid in the oxidation of other compounds. Additionally, it lowers the oxidation state of this chemical while increasing the oxidation state of other substances. In order to create the most stable arrangement, it goes through reduction.

\(Mn(CO)_5\) accepts electron from

\(⇒ Mn(CO)_5  +  e^- = [Mn(CO)_5]^-\)

Now, we see, in \(Mn(CO)_5\) oxidation number of \(Mn\) is

\(x  +  5(0) = -1\)

\( x = -1\)

Therefore, effective atomic number (EAN) of \(Mn(CO)_5\) is

\(25  +  1  + 2(5) = 36\)

Which is the stable configuration of \(Kr\)

So, the right answer is option is (2) \(Mn(CO)_5\)