Area bounded by $|x-1|≤2$ and $x^2-y^2 =1$, is
Answer & explanation
Correct answer: option 4
We have,
$|x-1|≤2⇔-1≤x≤3$
∴ Required area A is the area of the shaded region and is given by
$A=2\int\limits_{1}^{3}\sqrt{x^2-1}dx$
$⇒A=\left[x\sqrt{x^2-1}-\log_e(x+\sqrt{x^2-1})\right]_1^3$
$⇒A=\left\{3\sqrt{8}-\log_e(3+\sqrt{8})\right\}=6\sqrt{2}-\log_e(3+2\sqrt{2})$