A wire carries a current of 2.0 A. The number of electrons crossing through its cross-section in 10 s will be
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $1.25 × 10^{20}$
Given:
$I = 2.0 \, A$, $t = 10 \, s$
Charge flowing, $Q = I \times t = 2 \times 10 = 20 \, C$
Number of electrons, $n = \frac{Q}{e}$
$n = \frac{20}{1.6 \times 10^{-19}}$
$n = 1.25 \times 10^{20}$
Answer: $1.25 \times 10^{20}$ electrons