A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25 × 106 m above the surface of earth. If earth's radius is 6.38 × 106 m and g = 9.8 ms–2, then the orbital speed of the satellite is
Answer & explanation
Correct answer: option 2
v = \(\sqrt{\frac{GM}{r}}\)
v = \(\sqrt{\frac{GM}{R + h}}\)
g = \(\frac{GM}{R^2}\)
GM = gR2
v = \(\sqrt{\frac{gR^2}{R + h}}\)
v = R\(\frac{g}{R+h}\)
g = 9.8 m/s2 ; R = 6.38 x 106 m ; h = 0.25 x 106 m
Vo = 7.76 km/s