Let A= \(\left[\matrix{3&-4\\-2&1}\right]\) and B = \(\left[\matrix{\frac{-24}{8}&\frac{16}{4}\\ { 8 }^{ 1/3 } &1}\right]\), then the matrix A+B is 

None of these

 A+B = \(\left[\matrix{3&-4\\-2&1}\right]\) + \(\left[\matrix{-3&4\\2&1}\right]\)

A+B = \(\left[\matrix{3+(-3)&-4+4\\-2+2&1+1}\right]\) 

A+B = \(\left[\matrix{0&0\\0&2}\right]\)