Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

A generator develops an e.m.f. of 130 V and has a terminal potential difference of 125 V, when the armature current is 25 A. The resistance of the armature is

Options:

$ 0.2\Omega$

$0.25 \Omega$

$0.4 \Omega$

None 

Correct Answer:

$ 0.2\Omega$

Explanation:

$ R = \frac{E - V}{I} = \frac{130 - 125}{25} = 0.2 \Omega $