If one side of a square is increased by 35%, by what percentage another side is reduced so that its area remains same?

25\(\frac{25}{27}\)% 30\(\frac{25}{27}\)% 32% 33\(\frac{1}{27}\)%

25\(\frac{25}{27}\)%

Area = Side1 × Side2 *(When area is constant, then the relation b/w sides are inversely proportional) Side1  :  20  :   27 Side2  :  27  :   20 Side2 should be reduced by = 27 - 20 = 7 So, Reduce percent = \(\frac{7}{27}\) × 100 = 25\(\frac{25}{27}\)%