The current flowing through a wire as a function of time is given as: $I=3 t^2+2 t+5$ The charge flowing through any cross-section of the wire in first 2 s is:

22 C

The correct answer is Option (4) → 22 C

The total charge (Q) flowing through the wire in the first 2 seconds.

$Q=\int\limits_0^2I(t)dt$

$=\int\limits_0^2(3t^2+2t+5)dt$

$=[t^3+t^2+5t]_0^2$

$=22-0$

$=22C$