The current flowing through a wire as a function of time is given as: $I=3 t^2+2 t+5$ The charge flowing through any cross-section of the wire in first 2 s is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 22 C
The total charge (Q) flowing through the wire in the first 2 seconds.
$Q=\int\limits_0^2I(t)dt$
$=\int\limits_0^2(3t^2+2t+5)dt$
$=[t^3+t^2+5t]_0^2$
$=22-0$
$=22C$