Practicing Success
If a point charge q is placed at the centre of a cube what is the flux linked with each face of the cube? |
$\phi = \frac{q}{\epsilon_0}$ $\phi = \frac{q}{3\epsilon_0}$ $\phi = \frac{q}{2\epsilon_0}$ $\phi = \frac{q}{6\epsilon_0}$ |
$\phi = \frac{q}{6\epsilon_0}$ |
As cube is a symmetrical body with a faces and the point charge is at its centre, so electric flux linked with each face will be $\phi'= \frac{1}{6} \phi = \frac{q}{6\epsilon_0}$ |