Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

If a point charge q is placed at the centre of a cube what is the flux linked with each face of the cube?

Options:

$\phi = \frac{q}{\epsilon_0}$

$\phi = \frac{q}{3\epsilon_0}$

$\phi = \frac{q}{2\epsilon_0}$

$\phi = \frac{q}{6\epsilon_0}$

Correct Answer:

$\phi = \frac{q}{6\epsilon_0}$

Explanation:

As cube is a symmetrical body with a faces and the point charge is at its centre, so electric flux linked with each face will be

$\phi'= \frac{1}{6} \phi = \frac{q}{6\epsilon_0}$