If $x = 5.51, y = 5.52$ and $z = 5.57$, then what is the value of $x^3 + y^3 + z^3 - 3xyz$?
Answer & explanation
Correct answer: option 4
Given,
x = 5.51
y = 5.52
z = 5.57
We know that,
x3 + y3 + z3 – 3xyz = ($\frac{1}{2}$) (x + y + z) [(x – y)2 + (y – z)2 + (z – x)2]
= ($\frac{1}{2}$) × (5.51 + 5.52 + 5.57) [(5.51 – 5.52)2 + (5.52 – 5.57)2 + (5.57 – 5.51)2]
= ($\frac{1}{2}$) × 16.6 × [(-0.01)2 + (-0.05)2 + (0.06)2]
= 8.3 × [0.0001 + 0.0025 + 0.0036]
= 8.3 × 0.0062
= 0.05146