If $x = 5.51, y = 5.52$ and $z = 5.57$, then what is the value of $x^3 + y^3 + z^3 - 3xyz$?

0.05146

Given,

x = 5.51

 y = 5.52

z = 5.57

We know that,

x³ + y³ + z³ – 3xyz = ($\frac{1}{2}$) (x + y + z) [(x – y)² + (y – z)² + (z – x)²]

= ($\frac{1}{2}$) × (5.51 + 5.52 + 5.57) [(5.51 – 5.52)² + (5.52 – 5.57)² + (5.57 – 5.51)²]

= ($\frac{1}{2}$) × 16.6 × [(-0.01)² + (-0.05)² + (0.06)²]

= 8.3 × [0.0001 + 0.0025 + 0.0036]

= 8.3 × 0.0062

= 0.05146