The charge on capacitor of capacitance 20 μF as shown in figure given below is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 100 μC
The 20 μF and 10 μF capacitors are in series across the 15 V battery, so they carry the same charge, and that charge is the charge of the combination.
\( \displaystyle C_{\mathrm{eq}} = \frac{20\times10}{20+10} = \frac{20}{3}\,\mu\mathrm{F} \)
\( \displaystyle Q = C_{\mathrm{eq}}V = \frac{20}{3}\,\mu\mathrm{F}\times15\,\mathrm{V} = 100\,\mu\mathrm{C} \)