A is 1.5 times as efficient as B. A & B together complete the work in 12 days. In how many days, A alone can complete the work?
Answer & explanation
Correct answer: option 1
Given,
A : B = 3 : 2 (Efficiency)
⇒ A + B can complete a work in 12 days = (3 + 2) x 12 = 5 x 12 = 60 units, ..(Efficiency × Days = Total work)
⇒ Time required by A to complete the work alone = \(\frac{60}{3}\) = 20 days, ..(\(\frac{Work}{Efficiency}\) = Time)