Consider the 1M aqueous solution of the following compounds and arrange them in the increasing order of elevation in the boiling points.
A. C6H12O6
B. NaCl
C. MgCl2
D. AlCl3
E. Al2(SO4)3
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A < B < C < D < E
Elevation of boiling point is a colligative property: it depends on the number of solute particles. For an electrolyte the van’t Hoff factor i is included:
\( \Delta T_b = i\,K_b\,m \)
All the solutions have the same concentration and the same solvent (water), so ΔTb increases with i, the number of particles given by one formula unit on complete dissociation:
A. C6H12O6 — non-electrolyte, does not dissociate; i = 1
B. NaCl — \( \ce{Na^{+}} \) + \( \ce{Cl^{-}} \); i = 2
C. MgCl2 — \( \ce{Mg^{2+}} \) + \( \ce{2Cl^{-}} \); i = 3
D. AlCl3 — \( \ce{Al^{3+}} \) + \( \ce{3Cl^{-}} \); i = 4
E. Al2(SO4)3 — \( \ce{2Al^{3+}} \) + \( \ce{3SO4^{2-}} \); i = 5