The value of $Δ=\begin{vmatrix}(a^x +a^{-x})^2&(a^x -a^{-x})^2&1\\(a^y +a^{-y})^2&(a^y -a^{-y})^2&1\\(a^z +a^{-z})^2&(a^z -a^{-z})^2&1\end{vmatrix}$, is
Answer & explanation
Correct answer: option 3
Applying $C_1→C_1-C_2$, we get
$Δ=\begin{vmatrix}4&(a^x -a^{-x})^2&1\\4&(a^y -a^{-y})^2&1\\4&(a^z -a^{-z})^2&1\end{vmatrix}$ [Using: $(a+b)^2−(a - b)^ =4ab$]
$⇒Δ=4\begin{vmatrix}1&(a^x -a^{-x})^2&1\\1&(a^y -a^{-y})^2&1\\1&(a^z -a^{-z})^2&1\end{vmatrix}$ [Taking out 4 common from $C_1$]
$⇒Δ=4×0=0$ [∵ $C_1$ and $C_3$ are identical]