A can do \(\frac{1}{4}\)th part of work in 12 days, B can do 50% work in 20 days, and C can do \(\frac{1}{3}\)rd of the same work in 15 days. Who will complete the work first?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → B will complete first
Each person works at a steady rate, so the time for the whole work is the time for the part divided by the fraction of the work done. The one who needs the fewest days finishes first.
A: \(\frac{1}{4}\) of the work in 12 days, so the whole work in \(12\times4=48\) days
B: 50%, that is \(\frac{1}{2}\), of the work in 20 days, so the whole work in \(20\times2=\) 40 days
C: \(\frac{1}{3}\) of the work in 15 days, so the whole work in \(15\times3=45\) days