The minimum value of \(|x^{2}-3x+1|\) is

\(-4\) \(0\) \(-3\) None of these

None of these

\(\begin{aligned}\frac{dy}{dx}&=2x-3=0\\ x&=\frac{3}{2}\\ y&=\left|\frac{9}{4}-\frac{9}{2}+1\right|=\frac{5}{4}\end{aligned}\)