The minimum value of \(|x^{2}-3x+1|\) is1\(-4\)2\(0\)3\(-3\)4None of theseAnswer & explanation+Correct answer: option 4\(\begin{aligned}\frac{dy}{dx}&=2x-3=0\\ x&=\frac{3}{2}\\ y&=\left|\frac{9}{4}-\frac{9}{2}+1\right|=\frac{5}{4}\end{aligned}\)
