The minimum value of $|x^{2}-3x+1|$ is

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

The minimum value of $|x^{2}-3x+1|$ is

Options:

$-4$

$0$

$-3$

None of these

Correct Answer:

None of these

Explanation:

$\begin{aligned}\frac{dy}{dx}&=2x-3=0\\ x&=\frac{3}{2}\\ y&=\left|\frac{9}{4}-\frac{9}{2}+1\right|=\frac{5}{4}\end{aligned}$