In the figure 'G' is the centre of the circle. Find the angle ACB when ∠AGN = 150°. |
50° 60° 65° 75° |
75° |
We know that, The angle made by the chord at centre is double the angle made by it in a major segment of the circle. We have, ∠AGB = 150° ∠AGB = 2 × ∠ACB = 150° = 2 × ∠ACB = ∠ACB = 75° |