The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K . What is the composition of the liquid mixture if total vapour pressure is 600 mm Hg.
Answer & explanation
Correct answer: option 3
P=P0AXA + P0BXB
600=450x + 700(1-x)
600=450x + 700 - 700x
600-700=-250x
-100=-250x
x=0.4
1-x=0.6