In a hydrogen atom, an electron moves in an orbit of radius $5 × 10^{-11} m$ with a speed of $2.2 × 10^6 m/s$. The equivalent current is

$1.12 × 10^{-3} A$

The correct answer is Option (3) → $1.12 × 10^{-3} A$

Charge of electron $e = 1.6 \times 10^{-19} \, C$

Radius of orbit $r = 5 \times 10^{-11} \, m$

Speed $v = 2.2 \times 10^{6} \, m/s$

Time period of revolution: $T = \frac{2 \pi r}{v}$

$T = \frac{2 \pi (5 \times 10^{-11})}{2.2 \times 10^{6}}$

$T = \frac{3.14 \times 10^{-10}}{2.2 \times 10^{6}}$

$T \approx 1.43 \times 10^{-16} \, s$

Equivalent current: $I = \frac{e}{T}$

$I = \frac{1.6 \times 10^{-19}}{1.43 \times 10^{-16}}$

$I \approx 1.12 \times 10^{-3} \, A$

Final Answer: $1.1 \, mA$