A bike is purchased for ₹50,000. Its rate depreciates at 10% annually. In how many years will its value be ₹36,450?

3

Value depreciates every year by 10% .

So ,

Amount = Principal × ( 1 - \(\frac{r}{100}\) )^t

36450 = 50000 × ( 1 - \(\frac{10}{100}\) )^t

729 = 1000 × ( \(\frac{9}{100}\) )^t

\(\frac{729}{1000}\)= ( \(\frac{9}{100}\) )^t

( \(\frac{9}{10}\) )³ = ( \(\frac{9}{100}\) )^t

Time = 3 years