Practicing Success
Let a rod AB of length $l$ having resistance $r$ is moving perpendicular to a magnetic field B with constant velocity $v$. If the ends of the rod is connected to a wire PQRS of negligible resistance, then current passing through the wire will be: (see fig.) |
$\frac{Blv}{2r}$ $\frac{Blv}{r}$ $\frac{Blv}{4}$ $\frac{Blv}{4r}$ |
$\frac{Blv}{r}$ |
The correct answer is Option (2) → $\frac{Blv}{r}$ |