Let a rod AB of length $l$ having resistance $r$ is moving perpendicular to a magnetic field B with constant velocity $v$. If the ends of the rod is connected to a wire PQRS of negligible resistance, then current passing through the wire will be: (see fig.)
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{Blv}{r}$
The formula for the induced emf ε is -
$ε=Blv$
$∴I=\frac{ε}{R}=\frac{Blr}{r}$