Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:
For the curve \(y=xe^{x}\), the point
Options:
\(x=-1\) is a point of minimum
\(x=0\) is a point of minimum
\(x=-1\) is a point of maximum
\(x=0\) is a point of maximum
Correct Answer:
\(x=-1\) is a point of minimum
Explanation:
\(\begin{aligned}\frac{dy}{Dx}&=e^{x}(x+1)\\ \text{so }\frac{dy}{Dx}&=0\Rightarrow x=-1\\ \frac{d^{2}y}{dx^{2}}&=e^{x}(x+1)+e^{x}\\ \frac{d^{2}y}{dx^{2}}\left|_{x=-1}\right.&=e^{-1}>0\end{aligned}\)