CUET Preparation Today
If a charge Q is placed as shown in figure, find the flux through this cube.
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$\frac{Q}{\varepsilon_0}$ $\frac{Q}{2 \varepsilon_{0}}$ $\frac{Q}{4 \varepsilon_{0}}$ $\frac{Q}{8 \varepsilon_0}$ |
$\frac{Q}{4 \varepsilon_{0}}$ |
The correct answer is Option (3) → $\frac{Q}{4 \varepsilon_{0}}$ Total flux from the cube = $\frac{q}{ε_0}$ [By Gauss law] ∴ flux through this cube (eliminating two faces) = $\frac{1}{4}\frac{q}{ε_0}=\frac{q}{4ε_0}$ |
