If a charge Q is placed as shown in figure, find the flux through this cube.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{Q}{4 \varepsilon_{0}}$
Total flux from the cube = $\frac{q}{ε_0}$ [By Gauss law]
∴ flux through this cube (eliminating two faces) = $\frac{1}{4}\frac{q}{ε_0}=\frac{q}{4ε_0}$