Two capacitors of capacitances 2 μF and 4 μF are connected in parallel. A charge of 6 μC is given to the combination which gets shared. The ratio of the charges on the two capacitors, respectively will be

1 : 2

The correct answer is Option (3) → 1 : 2

Given: $C_1 = 2\ \mu F$, $C_2 = 4\ \mu F$, total charge $Q = 6\ \mu C$

For parallel connection:

Potential across each capacitor is same → $V_1 = V_2 = V$

Charge on each capacitor:

$Q_1 = C_1V$ , $Q_2 = C_2V$

Hence, $\frac{Q_1}{Q_2} = \frac{C_1}{C_2}$

$\frac{Q_1}{Q_2} = \frac{2}{4} = \frac{1}{2}$

Answer: Ratio of charges on the two capacitors = $1 : 2$