The ratio of energies of photons produced due to the transition of an electron of hydrogen atom from its i. second permitted energy level to the first level and |
1 : 2 3 : 4 2 : 1 4 : 1 |
3 : 4 |
The correct answer is Option (2) → 3 : 4 According to Bohr Model of hydrogen Atom - $E_n=-\frac{13.6}{n^2}eV$ $E_n$ → Energy at level n. $n$ → Principle Quantity Number $ΔE_{2→1}=E_1-E_2$ $=(-13.6)-(-3.4)=10.2eV$ $ΔE_{∞→1}=E_1-E_∞$ $=(-13.6)-0=13.6eV$ Ratio of energies: $\frac{ΔE_{2→1}}{ΔE_{∞→1}}=\frac{10.2}{13.6}=0.75$ |