In the given figure, O is the center of the circle. Circle has 3 tangents. ∠QPR = 50°, then what is the value (in degree) of ∠QOR ?

65° 67.5° 70° 75°

65°

∠PMO = ∠PNO = 90° (angle made by tangent) ∠MPO = ∠NPO = 25°   (ΔPMO ≅ ΔPNO) ∠QOR = 90° - \(\frac{1P}{2}\) = 90° - 25°          = 65°