In ΔACE, B and D are the points on side AC and CE respectively, such that BD ll AE, AE = \(\frac{9}{5}\)BD. What is the ratio of the area of ΔBCD to that of ΔAEC?
Answer & explanation
Correct answer: option 3
BD ll AE
ΔACE ∼ ΔBCD
\(\frac{area\;of\;ΔACE}{area\;of\;ΔBCD}\) = (\(\frac{AE}{BD}\))2 = \(\frac{81}{25}\)
ratio of area = 25 : 81