CUET Preparation Today
The flux of the electric field $\vec E=2×10^3\hat i N/C$ through a square of 10 cm, on a side whose plane is parallel to the xy plane is: |
$20 Nm^2/C$ $2×10^4 Nm^2/C$ $2×10^5 Nm^2/C$ 0 |
0 |
The correct answer is Option (1) → $20 Nm^2/C$ The electric flux through the square is - $\phi_E=\vec E.\vec A\cos(θ)$ $\phi_E=2×10^3×0.01×\cos 90°$ $=0 Nm^2/C$ |
