Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

The minimum value of the function $f(x)=2 x^2+5$ is

Options:

-1

5

$\frac{5}{2}$

Does not have any minimum value

Correct Answer:

5

Explanation:

$f(x)=2x^2+5.$

$x^2\ge0.$

$2x^2\ge0.$

$f(x)\ge5.$

$\text{Minimum value of }f(x)=5.$