ΔABC is an isosceles triangle with AB = AC = 13 cm. AD is the median on BC from A such that AD = 12 cm. The length of BC is equal to :

10 cm

Given,

AB = 13

AD = 12

then BC = ?

So, according to the pythagoras theorem =

H² = B² + P²

Here ABD is a right angled triangle

So, according to the pythagoras theorem =

13² = BD² + 12²

BD² = 169 - 144

BD² = 25

BD = \(\sqrt {25}\) = 5

So the value of BC = 2 $\times$ 5 = 10