A man covers \(\frac{2}{15}\) of a total journey by train, \(\frac{19}{45}\) of the journey by bus and the remaining 40 kms on boat.  His total journey (in kms) is?

90

Distance = LCM of the denominator of \(\frac{2}{15}\) and \(\frac{19}{45}\)

             = 45 Unit

Journey by train = 45 × \(\frac{2}{15}\) = 6 km

Journey by bus  = 45 × \(\frac{19}{45}\) = 19 km

Remaining Distance = 45 - (6 + 19) = 20 Units

20 Units → 40 km

45 Units → 90 km