The sum of the perfect square numbers between 120 and 300 is:

The correct answer is Option (3) → 1400

First find the smallest and largest whole numbers whose squares lie between 120 and 300: \(10^2=100\) is too small and \(11^2=121\) is the first; \(17^2=289\) is the last, since \(18^2=324\).

• The squares from \(11^2\) to \(17^2\): 121, 144, 169, 196, 225, 256, 289

• Sum of the first three: \(121+144+169=434\)

• Sum of the last four: \(196+225+256+289=966\)

• Sum of all seven squares \(=434+966=1400\)