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If tan θ + cot θ = 2, then what is the value of tanθ - cot θ ? |
0 5/8 1 3/4 |
0 |
We are given that :- tan θ + cot θ = 2 Let us assume that , θ = 45º tan45º + cot45º = 2 1 + 1 = 2 2 = 2 ( LHS = RHS ) So, θ = 45º Now, tan θ - cot θ = tan 45º - cot 45º = 1 - 1 = 0 |
