The co-ordinates of the point where the line $\frac{x+3}{3}=\frac{y-1}{-1}=\frac{z-5}{-5}$ cuts yz-plane are:

(0, 0, 0)

The correct answer is Option (2) → (0, 0, 0)

Equation of line: $\frac{x+3}{3}=\frac{y-1}{-1}=\frac{z-5}{-5}=t$

Parametric form:

$x=3t-3,\quad y=1-t,\quad z=5-5t$

The line cuts the $yz$-plane where $x=0$.

$0=3t-3\Rightarrow t=1$

Substitute $t=1$:

$y=1-1=0,\quad z=5-5(1)=0$

Coordinates: $(0,0,0)$