The co-ordinates of the point where the line $\frac{x+3}{3}=\frac{y-1}{-1}=\frac{z-5}{-5}$ cuts yz-plane are:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (0, 0, 0)
Equation of line: $\frac{x+3}{3}=\frac{y-1}{-1}=\frac{z-5}{-5}=t$
Parametric form:
$x=3t-3,\quad y=1-t,\quad z=5-5t$
The line cuts the $yz$-plane where $x=0$.
$0=3t-3\Rightarrow t=1$
Substitute $t=1$:
$y=1-1=0,\quad z=5-5(1)=0$
Coordinates: $(0,0,0)$