CUET Preparation Today
If A and B are square matrices of the same order, then $(A+B) (A-B)$ is equal to |
$A^2 -B^2$ $A^2-B^2+ BA- AB$ $A^2-BA-AB-B^2$ $B^2 + A^2 + AB- BA$ |
$A^2-B^2+ BA- AB$ |
The correct answer is Option (2) → $A^2-B^2+ BA- AB$ Expand: $(A+B)(A-B)=A(A-B)+B(A-B)$ $=A^{2}-AB+BA-B^{2}$ Since in general $AB\ne BA$, this cannot be simplified further. Final answer: $A^{2}-AB+BA-B^{2}$ |
