If A and B are square matrices of the same order, then $(A+B) (A-B)$ is equal to
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $A^2-B^2+ BA- AB$
Expand:
$(A+B)(A-B)=A(A-B)+B(A-B)$
$=A^{2}-AB+BA-B^{2}$
Since in general $AB\ne BA$, this cannot be simplified further.
Final answer: $A^{2}-AB+BA-B^{2}$