Practicing Success
Practicing Success
CUET Preparation Today
| A parallel plate capacitor is first charged using a battery and then isolated. A dielectric slab is then introduced between the plates. |
| How does energy vary in this case? |
energy increases
energy decreases remains constant can't say |
| energy decreases |
| When the capacitor is kept at a voltage, it gains charge. Now when the system is isolated, the charge present on capacitor cannot change because of law of conservation of charge. ∴ Charge always remains constant in isolated systems. initial capacitance < final capacitance and so from Conservation of charge, Energy $U = \frac{Q^2}{2C} $ decreases. |
