Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Kinetic Theory

Question:

The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

Options:

\(\frac{1}{\sqrt{2} n^2 \pi d^2}\)

\(\frac{1}{\sqrt{2} n^2 \pi^2 d^2}\)

\(\frac{1}{\sqrt{2} n \pi d}\)

\(\frac{1}{\sqrt{2} n \pi d^2}\)

Correct Answer:

\(\frac{1}{\sqrt{2} n \pi d^2}\)

Explanation:

Expression :

Mean free path : \(\lambda\) = \(\frac{1}{\sqrt{2} n \pi d^2}\)