$\int\frac{d(\cos θ)}{\sqrt{1-\cos^2θ}}$
Answer & explanation
Correct answer: option 4
$\int\frac{d(\cos θ)}{\sqrt{1-\cos^2θ}}=\sin^{-1}(\cos θ)$, [Put cos θ = x and integrate]
$\int\frac{d(\cos θ)}{\sqrt{1-\cos^2θ}}$
Correct answer: option 4
$\int\frac{d(\cos θ)}{\sqrt{1-\cos^2θ}}=\sin^{-1}(\cos θ)$, [Put cos θ = x and integrate]