What is the LCM of the fractions \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\) ?

\(\frac{8}{3}\) \(\frac{7}{3}\) \(\frac{8}{5}\) \(\frac{8}{31}\)

\(\frac{8}{3}\)

LCM of fraction = \(\frac{LCM\;of\;numerator}{HCF\; of\;denominator}\) The given fractions are :   \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\) LCM of 2, 8, 4 = 8 HCF of 3,15,27 = 3 The LCM of \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\) is = \(\frac{8}{3}\)