What is the LCM of the fractions \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\) ?
Answer & explanation
Correct answer: option 1
LCM of fraction = \(\frac{LCM\;of\;numerator}{HCF\; of\;denominator}\)
The given fractions are : \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\)
LCM of 2, 8, 4 = 8
HCF of 3,15,27 = 3
The LCM of \(\frac{2}{3}\), \(\frac{8}{15}\) and \(\frac{4}{27}\) is = \(\frac{8}{3}\)