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The population of a town is 6000. If males are increase by 5% and females are increase by 9% then population becomes 6500 after one year. Find the number of females in the town. |
1000 2500 4000 5000 |
5000 |
Total increase percentage = \(\frac{500}{6000}\) × 100% = \(\frac{25}{3}\) % Now, using allegation:
Therefore, No. of females = 5000 |
