The population of a town is 6000. If males are increase by 5% and females are increase by 9% then population becomes 6500 after one year. Find the number of females in the town.
Answer & explanation
Correct answer: option 4
Total increase percentage = \(\frac{500}{6000}\) × 100% = \(\frac{25}{3}\) %
Now, using allegation:
Therefore, No. of females = 5000