Area of the region bounded by $y=-1, y=2, x=y^3$ and $x=0$ is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) - $\frac{17}{4}$ sq. units
area = $-\int\limits_{-1}^0y^3dy+\int\limits_0^2y^3dy$
$⇒-\left[\frac{y^4}{4}\right]_{-1}^0+\left[\frac{y^4}{4}\right]_0^2$
$=\frac{16}{4}+\frac{1}{4}=\frac{17}{4}$