Practicing Success
Carbon monoxide contains approximately __________ of oxygen for each 1.00 g of carbon. |
0.23 g 2.66 g 1.33 g 4.11 g |
1.33 g |
The correct answer is option 3. 1.33 g. Here's how to determine the amount of oxygen in carbon monoxide for each 1.00 g of carbon: Stoichiometry: We can use the chemical formula of carbon monoxide (CO) to determine the ratio of carbon to oxygen. Molar masses: We need the molar masses of carbon (C) and oxygen (O) to convert grams to moles. Molar mass of \( C = 12.01\, \ g/mol\) Molar mass of \(O = 16.00\, \ g/mol\) Steps: Mole ratio: In CO, there is 1 atom of carbon for every 1 atom of oxygen. This translates to a 1:1 mole ratio between carbon and oxygen. Grams to moles: To find the moles of carbon in 1.00 g, divide by its molar mass: Moles of \(C = \frac{1.00\, \ g}{12.01\, \ g/mol} = 0.0833\, \ mol\) Using the mole ratio: Since the mole ratio is 1:1, the moles of oxygen are equal to the moles of carbon: Moles of \(O = 0.0833\, \ mol\) Moles to grams: Convert the moles of oxygen back to grams using its molar mass: Grams of \(O = 0.0833\, \ mol × 16.00 \, \ g/mol ≈ 1.33 g\) Therefore, for each 1.00 g of carbon in carbon monoxide, there are approximately 1.33 g of oxygen. So the answer is 1.33 g |