Carbon monoxide contains approximately __________ of oxygen for each…

The correct answer is option 3. 1.33 g.

Here's how to determine the amount of oxygen in carbon monoxide for each 1.00 g of carbon:

Stoichiometry: We can use the chemical formula of carbon monoxide (CO) to determine the ratio of carbon to oxygen.

Molar masses: We need the molar masses of carbon (C) and oxygen (O) to convert grams to moles.

Molar mass of \( C = 12.01\, \ g/mol\)

Molar mass of \(O = 16.00\, \ g/mol\)

Steps:

Mole ratio: In CO, there is 1 atom of carbon for every 1 atom of oxygen. This translates to a 1:1 mole ratio between carbon and oxygen.

Grams to moles: To find the moles of carbon in 1.00 g, divide by its molar mass:

Moles of \(C = \frac{1.00\, \ g}{12.01\, \ g/mol} = 0.0833\, \ mol\)

Using the mole ratio: Since the mole ratio is 1:1, the moles of oxygen are equal to the moles of carbon:

Moles of \(O = 0.0833\, \ mol\)

Moles to grams: Convert the moles of oxygen back to grams using its molar mass:

Grams of \(O = 0.0833\, \ mol × 16.00 \, \ g/mol ≈ 1.33 g\)

Therefore, for each 1.00 g of carbon in carbon monoxide, there are approximately 1.33 g of oxygen.

So the answer is 1.33 g