The rate constant, activation energy and the Arrhenius parameter at 27°C are $2.0 × 10^{-5}\, s^{-1},\, 100\, kJ\, mol^{-1}$ and $6.0 × 10^{14}\, s^{-1}$, respectively. The value of the rate constant at a very high temperature (T→∞) approaches to:

$6.0 × 10^{14}\, s^{-1}$

The correct answer is Option (3) → $6.0 × 10^{14}\, s^{-1}$

According to the Arrhenius equation:

$k = A e^{-E_a/RT}$

• As T → ∞, the term $\frac{E_a}{RT} → 0$
• Hence, $e^{-E_a/RT} → e^{0} = 1$

So,

$k \rightarrow A$

Given:

$A = 6.0 \times 10^{14}\ \text{s}^{-1}$