Product of the given reaction is:

The correct answer is Option (2) → \(RCH_2COOCH_2R'\)

TFPAA is trifluoroperoxyacetic acid, \( \ce{CF3CO3H} \). A peroxyacid converts a ketone into an ester by inserting one oxygen atom between the carbonyl carbon and one of the groups attached to it (the Baeyer-Villiger oxidation). No carbon atom is lost.

    \( \ce{RCH2-CO-CH2R'} \xrightarrow{\ce{CF3CO3H}} \ce{RCH2-CO-O-CH2R'} \)

Here both groups on the carbonyl carbon are primary alkyl groups (\( \ce{RCH2} \)– and R′\( \ce{CH2} \)–), so the oxygen enters between C=O and one \( \ce{CH2} \) group, and the product is the ester RCH₂COOCH₂R′.

Why the other options are incorrect

• Option (1) \(RCOOR'\) — Incorrect. Two \( \ce{CH2} \) groups are missing; the reaction inserts an oxygen and removes no carbon.

• Option (3) \(RCH_2COCH_2R'\) — Incorrect. This is the starting ketone; the peroxyacid adds an oxygen atom.

• Option (4) \(RCH_2COOCH_2R\) — Incorrect. Both ends carry R, so the group R′ of the ketone has been lost; the ester must keep both R and R′.

Note: The question is from beyond the NCERT textbook.