In quadrilateral PQRS, RM ⊥ QS, PN ⊥ QS and QS = 6 cm. If RM = 3 cm and PN = 2 cm, then the area of PQRS is
Answer & explanation
Correct answer: option 2
Area of trapezium = \(\frac{1}{2}\) × ( PN + RM ) × QS
= \(\frac{1}{2}\) × ( 2 + 3 ) × 6
= 15 cm²