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In quadrilateral PQRS, RM ⊥ QS, PN ⊥ QS and QS = 6 cm. If RM = 3 cm and PN = 2 cm, then the area of PQRS is |
13 cm2 15 cm2 14 cm2 11 cm2 |
15 cm2 |
Area of trapezium = \(\frac{1}{2}\) × ( PN + RM ) × QS = \(\frac{1}{2}\) × ( 2 + 3 ) × 6 = 15 cm² |
