Practicing Success
Let $P=\begin{bmatrix}5 & 2\\7 & 4\end{bmatrix}, Q= \begin{bmatrix}2 & 5\\3 & 8\end{bmatrix}$ and $R= \begin{bmatrix}2 & -1\\3 & 4\end{bmatrix}$, then the matrix S such that $QS- RP= 0, $ will be : |
$\begin{bmatrix}16 & 8\\56 & 32\end{bmatrix}$ $\begin{bmatrix}3 & -14\\4 & 17\end{bmatrix}$ $\begin{bmatrix}-1 & -13\\36 & 17\end{bmatrix}$ $\begin{bmatrix}-191 & -110\\77 & 44\end{bmatrix}$ |
$\begin{bmatrix}-191 & -110\\77 & 44\end{bmatrix}$ |