The area bounded between the curves \( y=2\sqrt{x} \), x-axis, \( x=0 \) and \( x=1 \) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \( \displaystyle\frac{4}{3} \) sq. units
The curve \( y=2\sqrt{x} \) lies above the x-axis on [0, 1], so
\( \displaystyle \text{Area}=\int_{0}^{1}2\sqrt{x}\,dx \)
\( \displaystyle =2\cdot\frac{2}{3}\left[x^{3/2}\right]_{0}^{1} \)
\( \displaystyle =\frac{4}{3} \)
NCERT Exemplar:
Application of Integrals
